Ben L. answered 04/21/20
TUTOR SPECIALIZING IN COLLEGE LEVEL CHEMISTRY COURSES
Assuming an elastic collision where kinetic energy and momentum are conserved, the answer is the following:
m1v1i + m2v2i = m1v1f + m2v2f -----> v1f = -v1i((m2v2f/m1v1i) - 1) Plug in numbers ----> v1f = 4 m/s.