
John M. answered 04/17/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
5Sec2Θ -20 = 0
Sec2Θ = 4
1/Cos2Θ = 4
Cos2Θ = 1/4 = 0.25
Take square root of both sides:
CosΘ = 0.5
Θ = Π/3
Sa T.
asked 04/17/20Solve for all the values of x. Give the answer in radians
5 sec^2 theta - 20 = 0 ( theta)
John M. answered 04/17/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
5Sec2Θ -20 = 0
Sec2Θ = 4
1/Cos2Θ = 4
Cos2Θ = 1/4 = 0.25
Take square root of both sides:
CosΘ = 0.5
Θ = Π/3
Arthur D. answered 04/17/20
Mathematics Tutor With a Master's Degree In Mathematics
5sec^2x-20=0
sec^2x-4=0
(secx-2)(secx+2)=0
secx=2
secx=-2
sec=1/cos
1/cos=2, therefore cos=1/2
1/cos=-2, therefore cos=-1/2
cosx=1/2 and cosx=-1/2
look on the unit circle
cosx=1/2 when x=∏/3 and x=5∏/3
cosx=-1/2 when x=2∏/3 and x=4∏/3
x=∏/3, 2∏/3, 4∏/3 and 5∏/3
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