A ball is thrown straight up with on initial speed of 90m/s. How fast and direction is the ball moving after 3s,6s,11s?

Answer 1

This is a kinematics problem. You can use the relation

v(t) = v₀ - gt

v₀ = 90 m/s

g = 9.8 m/s²

v(t) = 90 - 9.8t

with t in seconds and v(t) in m/s. Plug in your values of t in seconds. If v(t) is positive, it is moving upward. If v(t) is negative, it is moving downward.