Edward C. answered 02/04/15
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This is an arithmetic progression where the first term A(1) = 10 and each succeeding term is 4 more than the previous term. So A(2) = 14, A(3) = 18, A(4) = 22 and so on.
The Nth term will be equal to 10 plus 4 times (N-1), so numerically
A(N) = 4(N-1) + 10
So A(14) = 4*13 + 10 = 62 baskets made on the 14th day
Reva F.
01/09/18