Thomas H. answered 04/14/20
Mathematics Tutor
You start with this trigonometric identity:
cosθcosΦ - sinθsinΦ = cos(θ+Φ)
Now if θ and Φ are both equal to 150,
cos150cos150 - sin150sin150 = cos(150+150)
cos2150 - sin2150 = cos(300)
now we use another trigonmetric identity to express the square of the sine of 150
in terms of the cosine
cos2θ + sin2θ = 1 => sin2θ = 1 - cos2θ
so sin2150 = 1 - cos2150
and putting this in the other equation, we have
cos2150 -(1 - cos2150 ) = cos(300)
2cos2150 - 1 = cos(300)
2cos2150 = 1 + cos(300)
cos2150 = (1/2)(1+ cos(300))
cos150 = sqrt((1/2)+(sqrt(3)/2))