Using x instead of theta:
tan x = sin x/cos x
If cos x is negative and tan x is also negative, then sin x must be positive, which places us in quadrant II.
since cos^2 (x) + sin^2 (x) = 1, (-5/13)^2 + sin^2 (x) = 1, 25/169 + sin ^2 (x) = 1, sin^2(x) = 144/169 and sin x = 12/13 (since it is positive)
tan (x) = sin(x)/cos(x) = -12/5
cot (x) = 1/tan(x) = -5/12
sec (x) = 1/cos(x) = -13/5
csc(x) = 1/sin(x) = 13/12
the arccos(-5/13) = 112.6, the reference angle is (180-112.6) = 67.4