Inactive Tutor answered 04/12/20
cos2(2x) = 1 + cos(4x)
sin2(2x) = (1-cos(4x))/2
substituting the two values in we get:
cos2(2x)sin2(2x) = (1 + cos(4x)).(1-cos(4x))/2
Inactive Tutor
you don't solve it any further as they are in the first powers of cosine.04/12/20
Rebecca C.
How do you solve it04/12/20