Find the values of x

Question

3x² + 4y² = 48

x² - 6y² = -50

Answer 1

For the second equation, manioulate it until x^2= -50-6y^2 and then substitute x^2 in the first equation for -50-6y^2. Solve for Y and then solve for X.

Answer 2

Why don't you eliminate the y variable by doing the following:

Multiply the first equation by 3.

Multiply the 2nd equation by 2.

Add these 2 equations together.

Solve the resulting single variable equation for x.

Answer 3

3x^2 + 4y^2 = 48

x^2 - 6y^2 = -50

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-3 * eq2 + eq1

22y^2 = 198

y^2 = 9

y = +or- 3

3x^2 + 4y^2 = 48

3x^2 + 4(9) = 48

3x^2 + 36 = 48

3x^2 = 12

x^2 = 4

x = +or- 2

{+or- 2, +or- 3} ---> (2,3) (2,-3) (-2,3) (-2,-3)