The mass of an object double while its speed is halved. What happens to the objects a) momentum b)Kinetic Energy

Question

Please explain it in detail

Answer 1

(a)

p₁ = mv

m → 2m

v → v/2

p₂ = (2m)(v/2) = mv = p

No change in momentum.

(b)

K₁ = mv²/2

m → 2m

v → v/2

K₂ = (2m)(v/2)²/2 = (1/2)mv²/2 = K/2

Kinetic energy drops by half.