
Randall G. answered 04/07/20
Physics and Applied Physics Ph.D.
Although the magnetic force is a "velocity dependent force" as in: FB = q(v×B) (× here is the cross-product), the cross-product "forces" (a good place for a pun here) the magnetic force, FB to always be perpendicular to both the velocity, v, and the magnetic field, B.
Since work is defined as W = F•D, where • is the dot-product and D is given by the product of the particle velocity and the time, vt, you can see that W must be equal to zero. This is because W = FB·vt·cos(θ), where θ--the angle between the initial magnetic force, FB, and the velocity, v--is equal to 90° due to the cross product between v and B in the original definition of FB = q(v×B).
In other words, the magnetic force causes charged particles to circle around the magnetic field lines, always perpendicular to the particle's linear velocity.