Yefim S. answered 04/06/20
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Math Tutor with Experience
tanA/2 = sinA/2/cosA/2 = 2sinA/2·cosA/2/2cos2A/2 = sinA/(1 + cosA) or
tanA/2 = sinA/2/cosA/2 = 2sin2A/2/(2sinA/2·cosA/2) = (1 - cosA)/sinA
Muhammad M.
So they both are correct?04/06/20