
Patrick B. answered 04/06/20
Math and computer tutor/teacher
cos(2T-T) = cos2T cos T + sin 2T sin T = sqrt(3)/2
cos(T) = sqrt(3)/2
T = 30, so the solution is flavors of 30 degrees
30,150,210,330
check:
cos(30) cos(60) + sin(30)sin(60) =
sqrt(3)/2 * 1/2 + (1/2)(sqrt(3)/2) =
sqrt(3)/4 + sqrt(3)/4 =
sqrt(3)/2
yes