Given tanx = 2/5 and cscx < 0, find cscx and secx.

Answer 1

Tan (2/5) is positive in Quadrant 1 and 3. For Csc to be negative, Quadrant 3 is to be used.

This yields the hypotenuse = √( 2² + 5²) = √(29

Then Csc(x) = -1/Sin(x) = -√29/2 and Sec(x) = -√29/5