cos (x) = x
f(x) = x - cos(x)
f'(x) = 1 + sin(x)
a1 = a0 - f(a0)/f'(a0)
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.
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an+1 = an - f(an)/f'(an)
Take a0 as 1
a1 = 1 - (1 - cos(1))/(1 + sin(1))
a2 = a1 - f(a1)/f'(a1)
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.
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Danny L.
asked 04/01/20cos(x)= x
Thanks!
cos (x) = x
f(x) = x - cos(x)
f'(x) = 1 + sin(x)
a1 = a0 - f(a0)/f'(a0)
.
.
.
an+1 = an - f(an)/f'(an)
Take a0 as 1
a1 = 1 - (1 - cos(1))/(1 + sin(1))
a2 = a1 - f(a1)/f'(a1)
.
.
.
Patrick B. answered 04/01/20
Math and computer tutor/teacher
cos x = x
cosx - x = 0
f(x) = cos x - x
x = 0.739
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Danny L.
I'm still confused by this. So the answer would be 1 becuase ao is 1?04/01/20