Solve the equation for θ if 0° ≤ θ < 360°. (Enter your answers as a comma-separated list.) sqrt2 sec θ = 2

Answer 1

secT = 2/sqr2

cosT =sqr2/2

Theta = 45 degrees, 315 degrees

It's a right triangle with angles 45-45-90 degrees and sides in ratio sqr2-sqr2-2

4=2+2, 2^2 = (sqr2)^2 + (sqr2)^2

It's positive secant or cosine so it's in quadrant I and IV

secant is the inverse of the cosine