First, find the center: (((-2)+(-2))/2, ((-4)+10)/2) = (-2, 3)
Then, find the length of the major axis: 14 = 2a
The length of minor axis: 10 = 2b
Apply formula, you'll get:
((x+2)2/72) + ((y-3)2/52) = 1
Rudy O.
asked 03/31/20Endpoints of the major axis (vertices) at (-2,-4) and (-2,10) and has a minor axis of length 10.
First, find the center: (((-2)+(-2))/2, ((-4)+10)/2) = (-2, 3)
Then, find the length of the major axis: 14 = 2a
The length of minor axis: 10 = 2b
Apply formula, you'll get:
((x+2)2/72) + ((y-3)2/52) = 1
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