Bonnie J. answered 03/29/20
Experienced Math Tutor Excellent Communicator
x=1 x=1 x=0 x=-4
(x-1) (x-1) (x) (x=4)
(x-1)(x-1) = x^2 - 2x +1
(x)(x^2 -2x +1) = x^3 - 2x^2 + x
(x+4)(x^3 - 2x + x) = x^4 + 2x^3 -7x^2 + 4x
Replace (5,288) for (x,y)
y = a (x^4 + 2x^3 - 7x^2 + 4x)
288 = a [5^4 + 2(5)^3 - (5)^2 + 4(5)]
288 = a (720)
288/720 = a
a = 2/5
y = 2/5 (x^4 + 2x^3 - 7x^2 + 4x)
y = 2/5x^4 + 4/5x^3 - 14/5x^2 + 8/5x
Bonnie J.
My pleasure!03/29/20
Darlene F.
Thank you!03/29/20