For problem 1, if the zeros are 3 and -5, then the factors are (x - 3) and (x + 5). Since 3 has a multiplicity of 2, then the polynomial could be written as (x - 3)²(x + 5) in factored form.
For problem 2, the factors are x - 0 or x, along with (x + 2) and (x - 4).
This fifth-degree polynomial in factored form would be x³(x + 2)(x - 4). The x is cubed because x = 0 has a multiplicity of 3.
Problems 3 and 4 can be handled in the same manner. There is a theorem that states if x = k is a zero of a polynomial, then (x - k) is a factor of the polynomial.