
Stanton D. answered 03/28/20
Tutor to Pique Your Sciences Interest
Hi Oscar A.,
Seemingly a hard problem, but not once you master the concepts.
1) unpolarized->polarized = intensity 0.5
2) polarized -> polarized different direction = cos(angle between the polarization direction axes)
= cos (45 degrees) = cos (.pi./4) = 2^0.5/2 So that's 0.35 as a product.
Once the light is polarized, passing through ideal polarizers in the same direction doesn't diminish it at all.
Now here's a though-question for you: ine conceives of the polarizers as always lying perpendicular to the th of the light. But what if one were tilted, either sideways, or to-and-away?
-- Cheers, -- Mr. d.

Stanton D.
Sorry, some mangled text. "Thought-question", "one conceives" and "the path of the light"03/28/20