Show that the point is on th eunit circle

Question

(3/4, √(7)/4)

We need to show that the point satisfies the equation of the unit circle, that is, x² + y² =  _____________

x^2 + y^2 = (_____)^2 + (-√(7)/4)^2

___________- + 7/16

Is the point on the unit circle?

Thanks!

Answer 1

9/16 + 7/16 = 16/16 = 1

The point's on the unit circle.

Square the x coordinate, square the y coordinate

Sum them and if they equal one, the point's on the

unit circle, with center at the origin.

3/4 squared = 9/16

(sqr7)/4 squared = 7/16

Together they add to 16/16 = 1

The point (3/4, -(sqr7)/4) is also on the unit circle

The points (-3/4, (sqr7)/4) and (-3/4, -(sqr7)/4) are also on the unit circle.