The formula for this questions is F = ILBsinθ
- if the wire runs N to S, then the angle with the magnetic field is 0, and sin0 is 0, and 0 times the other parameters is 0.
- if the wire runs E to W, then the angle is 90. sin90 is 1, so the force F is ILB = 75 * 35 * 0.5x10-4
- if the wire is 30º north of east, then the angle between the wire and the magnetic field (running S to N) is 60º. sin60 is 0.866, so the force F = 75*35*0.5x10-4 * 0.866