A solenoid with 25 turns per centimeter carries a current of 25 mA

Question

What is the magnetic field in the interior of the coils?

Answer 1

The magnetic field at the center of a solenoid is given by: B = µ₀NI.

The constant µ₀ is equal to 4π*10^-7 N•m²•kg^-2.

The given number of turns is 25 cm^-1, which can be converted to 25*10² m^-1.

The given current 'I' is 25 mA, which is 25*10^-3 A.

Therefore..

B = µ₀NI

B = (4π*10^-7 N•m²•kg^-2)(25*10² m^-1)(25*10^-3 A) = 9.1*10^-5 T

The unit of the final answer is in teslas, which can be broken down to kg•s^-2•A^-1.