A round loop of wire carries a current of 100 A, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a magnetic field of 0.324 T.

Question

1)What is the torque on the loop?

2)What is the torque on the loop if the angle decreases to 10∘?

3)What is the torque on the loop if the angle increases to 50∘?

Answer 1

Torque On A Current Loop is given by (Number Of Turns Of Loop)×(Current Through Loop)×(Area Enclosed By Loop)×(Magnetic Field Strength)×(Sine Of Angle Formed By Magnetic Field Direction And A Vector Perpendicular To The Plane Of The Loop).

From τ = NIABsin θ, write τ = (1 Turn)×(100 Amperes)×(π(0.1 Meter)²)×(0.324 Tesla)×(sin θ).

Then write:

A. τ = (1 Turn)×(100 Amperes)×(π(0.1 Meter)²)×(0.324 Tesla)×(sin 30°) or 0.5089380099 Joule.

B. τ = (1 Turn)×(100 Amperes)×(π(0.1 Meter)²)×(0.324 Tesla)×(sin 10°) or 0.1767523159 Joule.

C. τ = (1 Turn)×(100 Amperes)×(π(0.1 Meter)²)×(0.324 Tesla)×(sin 50°) or 0.7797382687 Joule.

Final answers are in Proper Decimal Fractions of a Joule because Amperes×Meter²×Tesla amounts to

Amperes×Meter²×Newton Per (Ampere•Meter) or "Newton•Meter" or "Joule", reflecting a Force acting through a Distance and showing Kinetic Energy or performing Work.