
Tracy R. answered 02/02/15
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Arithmetic to Algebra and the ASVAB
The mechanics of this problem are to calculate the volume of the box, calculate the volume of the 12 cylinders (cans) and then subtract the cylinder volume from the box volume. The problem states to use the value of 3.14 for pi.
Calculate the Dimensions of the Box.
There are 12 cylinders. Each cylinder has a diameter of 10 cm and a height of 20 cm. Arrange the cylinders in a rectangular configuration of 3 rows and 4 columns (other configurations are possible). So, the length of the box is the diameter of one cylinder times 4 which equals 40 cm. The width of the box is the diameter of one cylinder times 3 which is 30 cm. The height of the box is equal to the height of a cylinder which is 20 cm.
So, the volume of the box equals 40 x 30 x 20 which is 24,000 cm^3
Calculate the Volume of the Cylinders
All cylinders have the same dimension: diameter = 10 cm and height = 20 cm. The volume of a Right Cylinder is V = pi * r^2* h, where r = the radius and h = the height.
Volume of one cylinder: V = 3.14 * 5^2 * 20
Volume = 1570 cm^3
Volume of 12 cylinders: 12 * 1570 = 18,840 cm^3
Calculate the Difference in Volume Between the Box and the 12 cylinders
24,000 – 18,840 = 5,160 cm^3
So, the answer is 5,160 cm^3