rotational motion of a stick

Question

a meter stick is pivoted at the 50 cm mark, a force of 5.0 N is applied at 78 cm mark perpendicular to the stick, what is the torque?

Answer 1

The torque about the pivot point is

τ = rFsinθ

r = (0.78 - 0.50) m = ? m

F = 5.0 N

θ = 90°

Plug in the numbers and get τ in units of mN.