write as a function of y in x if y^(3)-3y^(2)+3y=3(x+1)

Answer 1

y³ - 3y² + 3y = 3(x + 1)

y³ - 3y² + 3y - 1 = 3x + 2 --> left side of the equation is the expansion of (y - 1)³

(y - 1)³ = 3x + 2

y - 1 = ³√(3x + 2)

y = 1 + ³√(3x + 2)