physics magnetic force

Question

An electron moves with a velocity of 107 m/s in the x-y plane at an angle of 45∘ to both the +x and +y axes. There is a magnetic field of 3.5 T in the +y direction.

Determine the magnitude of the magnetic force on the electron.

Answer 1

Hi Annie!

The equation that determine the magnitude of force on a charged particle from a magnetic field, or the Lorenz force, is F = qvB sin (theta), there (theta) is the angle between the velocity and the magnetic field.

So . . . F = (1.6 x 10-19 C)(107 m/s)(3.5 T)(sin 45 degrees) = 4.24 x 10^-17 N