Mark M. answered 03/10/20
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
x6 - 2x3 + 1 + x +
(x3 - 1)(x3 - 1)
(x - 1)(x2 + x + 1)(x - 1)(x2 + x + 1)
From here you should be able to determine the zeros.