
Arturo O. answered 03/06/20
Experienced Physics Teacher for Physics Tutoring
Draw a picture of the two electric field vectors at P (from the two charges) and note that the net field must point in the negative vertical direction. The fields from the two charges have the same magnitude, so it is sufficient to find the vertical component of one field, multiply it by 2, and point it in the negative vertical direction. Assuming the vertical axis is the y-axis, define
sinθ = a / √(x2 + a2)
Then
E = 2Ey = 2[kQ / (x2 + a2)] sinθ
E = 2[kQ / (x2 + a2)] [a / √(x2 + a2)]
E = 2kQa / (x2 + a2)3/2