Richard B. answered 03/06/20
Math, Physics, EE, Digital Photography, Photoshop, Drums
You can calculate the field at point P due to the positive charge using the standard Coulomb's constant equation to get the magnitude. Then you have to break down the magnitude into the X and Y component directions. Since the charge at point P produced by the positive charge is away from the charge and the charge produced at point P due to the negative charge is toward the negative charge, the X component of each charge will cancel out. However the Y component of each charge will go in the downward direction from each charge so when you calculate the Y component from one charge you just need to double it. So the magnitude of the charge would be KQ1/Distance squared or KQ1/a^2+x^2. But to calculate the Y complement of each charge you would have to multiply it by the sin of the angle whose tangent is equal to a/x, then multiply that by 2. So the final equation becomes 2*KQ/(a^2+X^2) all times sin(tan^-1(a/x)). Sorry but I tried pasting a figure that I created in PowerPoint into this answer but it wouldn't let me.