Denise G. answered 03/03/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
csc x - sin x = cos x cot x Will manipulate the left side - Turn csc into sin
1/sin x - sin x Get a common denominator
1/sinx - sin x/sin x
(1-sin2x)/sin x Pythagorean identities, 1-sin2x sub in cos2x
cos2x/sin x Split up to cos2x
(cos x)(cos x/sin x) cos x/sin x = cot x
cos x cot x = cos x cot x
tan2x/(1+sec x) = (1-cos x)/cos x Will manipulate the left side using x instead of theta for the variable for ease of typing, Pythagorean identities tan2x=sec2x-1
(sec2x-1)/(1+sec x) Factor the numerator, it is difference of squares
(sec x+1)(sec x -1)/(1+sec x) (sec x+1) and (1+sec x) cancel out
(sec x -1) Change sec to cos
1/cos x - 1 Get a common denominator
1/cos x - cos x /cos x
(1-cos x)/cos x = (1-cos x)/cos x