A 1.6-m wire is wound into a coil with a radius of 3.2 cm.

Question

A 1.6-m wire is wound into a coil with a radius of 3.2cm .If this coil is rotated at 94 rpm  in a 6.3×10⁻²-T

 magnetic field, what is its maximum emf?

 

Answer 1

The formula for the maximum induced emf is given by ε_max = NBAω

From the question B = 6.3x10^-2T, A = πr² = 3.2x10^-3m² and ω = (94x2π/60)rad/s = 9.8rad/s and N =?

Solve for N = L/C = L/2πr = 1.6m/2πx3.2x10^-2 m = 8 turns

Now plug in these numbers into ε_max = NBAω = 8(6.3x10^-2T)(3.2x10^-3m² )(9.8rad/s) = 0.016V = 16mV.