create a very particular calculator that works with 3 integer numbers at a time rather than the usual 2 in regular calculators.

Question

1. So, first, ask the user to enter the desired operation (use cin) and store the value in a variable named operation. The user input will consist of a single letter or symbol. Entering:

a) ‘a’ or ‘A’ gives the average (shown as a fractional number)

b) 'M' gives the largest number

c) 'c' or 'C' gives the middle number

d) 'o' or 'O' gives the count of how many of the three numbers are even

e) 'p' or 'P' tests whether any of the 3 numbers is divisible by 2, 3 and 5

f) 'e' or 'E' tests whether all of the 3 numbers are different

g) 's', 'S' or '+' tests whether the sum of any 2 numbers adds to the 3rd one

h) ‘m’ gives the sum of all numbers between the first and second number with a step increment given by the third number

Answer 1

using namespace std;

#include <iostream>

int GO()

{

int X,Y,Z;

char operation;

cout << " Please input the first # :>";

cin >> X;

cout << "Please input the 2nd # :>";

cin >> Y;

cout << "Please input the 3rd # :>";

cin >> Z;

cout << "Please input the operation :>";

cin >> operation;

switch (operation)

{

case 'A':

case 'a':

{

int total = X+Y+Z;

int remainder = total %3;

int n = total/3;

cout << " The average is " << n;

if (remainder==0)

{

cout << endl;

}

else

{

cout << " and " << remainder << "/3" << endl;

}

break;

} //A , a

case 'M':

{

int temp = (X>Y) ? X : Y;

int maxInt = ( temp > Z) ? temp : Z;

cout << " The max is " << maxInt << endl;

break;

} //M

case 'C':

case 'c':

{

int A[3];

A[0]=X;

A[1]=Y;

A[2]=Z;

//bubble sort

if (A[0]>A[1])

{

int temp = A[1];

A[1] = A[0];

A[0] = temp;

}

if (A[1]>A[2])

{

int temp = A[1];

A[1] = A[2];

A[2] = temp;

}

if (A[0]>A[1])

{

int temp = A[1];

A[1] = A[0];

A[0] = temp;

}

cout << " sorted... "<< endl;

for (int iLoop=0; iLoop<3; iLoop++)

{

cout << A[iLoop]<< endl;

}

cout << "The middle # is " << A[1] << endl;

break;

} //C,c

case 'O':

case 'o':

{

int even_count = 0;

if ((X%2)==0)

{

cout << X << " is even " << endl;

even_count++;

}

if ((Y%2)==0)

{

cout << Y << " is even " << endl;

even_count++;

}

if ((Z%2)==0)

{

cout << Z << " is even " << endl;

even_count++;

}

cout << even_count << " of the 3 integers are even " << endl;

break;

} //O,o

case 'P':

case 'p':

{

if (

((X%2)==0) && ((X%3)==0) && ((X%5)==0)

)

{

cout << X << " is divisible by 2, 3, and 5 " << endl;

}

if (

((Y%2)==0) && ((Y%3)==0) && ((Y%5)==0)

)

{

cout << Y << " is divisible by 2, 3, and 5 " << endl;

}

if (

((Z%2)==0) && ((Z%3)==0) && ((Z%5)==0)

)

{

cout << Z << " is divisible by 2, 3, and 5 " << endl;

}

break;

} //P,p

case 'E':

case 'e':

{

if ((X==Y) && (Y==Z))

{

cout << " The three integers are equal " << endl;

}

else

{

if ((X==Y) || (Y==Z) || (X==Z))

{

cout << " Two of the three integers are equal " << endl;

}

else

{

cout << " The three integers are different " << endl;

}

}

break;

} //'E','e'

case 'S':

case 's':

{

if (

((X+Y)==Z) ||

((X+Z)==Y) ||

((Y+Z)==X)

)

{

cout << " One of the integers is a sum of the other two " << endl;

}

else

{

cout << " None of the integers is the sum of the other two " << endl;

}

break;

} //S,s

case 'm':

{

int N = X+1;

int sum = 0;

do

{

sum += N;

N += Z;

} while (N<Y);

cout << " The sum of the integers between " << X << " and " << Y << " that differ by " << Z << " is " << sum << endl;

break;

}

} //m

return 0;

}

int main()

{

return(GO());

}