Hadassah J.
asked 02/24/20
Fine the domain f^-1(x)=x^2/2+2
Patrick B.
answered 02/24/20
Math and computer tutor/teacher
y = (1/2)x^2 + 2
Swaps the vars:
x = (1/2)y^2 + 2
Solves for y
(x-2) = (1/2)y^2
2(x-2) = y^2
y = sqrt(2(x-2))
Domain:
2(x-2) >=0
2x - 4 >= 0
2x >= 4
x>=2
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