Eduardo L. answered 03/01/20
I'm basically a Mexican version of Spock
y=x2-2x-3=0; (x-3)(x+1)=0 therefore we have x-intercepts at x=-1, and x=3.
find min:
y'=2x-2=0
min @ x=1
when x=1, y=(1)2-2(1)-3=-4
we draw a line at the x-axis, and we have a minimum at x=1 of -4m
this is 2m above the ground, so what this means is that the starting point must be
6m above the ground (2m + 4m = 6m)