Mukul S. answered 02/21/20
Experienced & Expert Physics/Math Tutor
Before we attempt to answer these, let's review the definition of the coefficient of friction μ. It measures friction between two surfaces in contact.
If two surfaces in contact have a force FN, in a direction normal to them, then the frictional force, Ff, which acts parallel to the surfaces is given by
Ff = μ. FN
We will use this definition of μ to answer the questions.
Ques 43: A 200lb crate on the floor exerts a force normal to the surfaces in contact (create & floor). So,
FN = 200 lbs-force
Note that in this problem, it is not necessary to convert the force units to a specific system (e.g. MKS) unless the question requires it. Your answer for Ff will simply be in the same units as those for FN.
The minimum force, Fmin required to drag the crate parallel to the floor must equal (and just exceed) the Frictional force Ff. Therefore,
Fmin = Ff = μ. FN
Substituting μ=0.6 and FN = 200lbs
Ff = 120lbs
Ques 44: Here you are given the frictional force (240N) and the normal force (60 Kg). Note that you must have both forces in the same units to calculate μ. Convert weight to Newtons first and then divide Ff with FN
Ques 45: The picture below shows the various forces acting on the block.
When θ = 40, the force acting to drag the block down is just equal to the force of friction that prevents the block from sliding.
Ff = Mg.Sinθ
The force acting normal to the inclined block surface is
FN = Mg.Cosθ
By Definition, coefficient of friction
μ = Ff / FN
You can now calculate μ.