Commenwealth A.
asked 02/21/20systems of equation and matrice
A piggy bank contains only nickels, dimes, and quarters. There is a total of 105 coins and the total value of those coins is $10.75.
- Find a general solution of the number of each coin.
- List three possible specific solutions.
Show your work for full credit.
1 Expert Answer
Raymond B. answered 02/21/20
Math, microeconomics or criminal justice
5N+10D+25Q=1075
N+D+Q=105
Let Q = a maximum 1075/25=43. One solution is Q=43, N=D=0 But 43 does not equal 105
Let Q=40 That equals 25x40=1000 15 nickels add 75 but 40+15 is less than 105
Q has to be less than 40
Let Q=30 30x25=750 1075-750=325 65 nickels would add 5x65=325
Q=30 D=0 and N=65 is one solution
Other solutions would have have Q<30 Q=29 means one quarter has to be replaced with one coin either N or D, and switch some Ns for D. 29x25=725 1075-725=350. 63=N 5xx63=315 add 3 dimes
3x10+315+725 is 5 cents short of 1075
Q=27 27x25=675 Need N&D worth 400 where N+D=78 That's two equations 5N+10D=78
also 5N=5D=390 subtract to get 5D=390-78=312 D= a fraction, it won't work
(Q,D,N)=(30,0,65) is one solution
In general, N+D+Q=105, 5N+10D+25Q=1075 5N+5D+5Q=525 D+4Q=110
Pick a Q, it has to fit in that equation and get an integer result for D.
D=110-4Q=2(55-2Q) Q has to be <27
Try Q=26, 425 left for N&D. N+D=79 and 5N+10D=425 5N+5D=5(=7079)=395 425-395=30 5D=30, D=6
Another solution is (Q,D,N)=(26,6,7)
(Q,D,N) = (30,0,65), (26,6,7)
A third solution would necessarily involve a Q < 26
Try Q=25, then D+4Q=110 means D=10 N=70
25x25 + 10x10 + 5x70 = 625+ 100 + 350 = 1075
another solution is (Q,D, N) = (25, 10, 70)
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Tom K.
We require at least 2 quarters, as 1 quarter would mean 10.50 left for dimes and nickels meaning at least 105 coins plus the quarter is at least 106 coins. Solution 1: 2 quarters, 102 dimes, 1 nickel (2 * 25 =50; 1075 - 50 = 1025 for 103 coins means 102 dimes and 1 nickel). Each additional quarter requires 15 cents more than with a dime, so as nickels are 5 cents less than dimes, we need 15/3 = 3 nickels replacing 3 dimes. Thus, we see that 25 + 3 * 5 = 4 * 10 (4 dimes replaced by 1 quarter and 3 nickels means 40 cents on each side and 4 coins on each side). Thus, the solution is 2 + x quarters; 102 - 4x dimes; 1 + 3x nickels. The total number of coins is 2+x + 102 - 4x + 1 + 3x = 105 The total money is (2+x)25 + (102-4x)10 + (1+3x)5 = 50 + 1020 + 5 + 25x - 40x + 15x = 1075 As nickels are >= 0, 1+3x >= 0, so x >= -1/3 or x >= 0 102-4x >= 0 so x <= 25 1/2 or x <= 25 General Solution: 2 + x quarters; 102 - 4x dimes; 1 + 3x nickels 0 <= x <= 25 26 solutions.02/21/20