Mark M. answered 02/21/20
Mathematics Teacher - NCLB Highly Qualified
2 lengths = 550 - 5 widths
1 length = 275 - 2.5 width
Area = w(275 - 2.5w)
Area = -2.5w2 + 275w
Maximum at w = 55 (Max, occurs at -b / 2a)
Danny L.
asked 02/21/20
(a) Find a function A that models the total area of the four pens. (Use w to represent the width of the field.)
(b) Find the largest possible total area of the four pens.
Thanks!
Mark M. answered 02/21/20
Mathematics Teacher - NCLB Highly Qualified
2 lengths = 550 - 5 widths
1 length = 275 - 2.5 width
Area = w(275 - 2.5w)
Area = -2.5w2 + 275w
Maximum at w = 55 (Max, occurs at -b / 2a)
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