
Frank A. answered 02/18/20
Knowledge, experience and insight from decades of teaching physics.
Eunjin L.
20°C is close to room temperature and the speed of sound in air at room temperature is approximately 340ms-1.
Using the wave equation v = f•λ, and substituting the values of speed and frequency, we get
λ = 340m/s÷39000Hz
= 0.0087m
Using the speed of sound as before, and substituting in the equation s=v•t
we get s = 340m/s•0.150s
= 51m.
Now the sound travels a total of 51m which means 51/2m up and 51/2m back so the object is 25.5m away.
I hope this helps. Mr. A
Eunjin L.
Thank you so much, Mr. A! I understand it with your explanation better now.02/18/20