physics question

Question

The value of specific heat for copper is 390 J/KG , for aluminun is 900  ,and for water is 4186 .

What will be the equilibrium temperature when a 275 G block of copper at 245 celsius is placed in a 145 aluminum calorimeter cup containing 875 g  of water at 12.0 CELSIUS ?

Answer 1

Apply the law of heat exchange: Heat lost by hot object(s) = heat gained by cold object(s)

Since aluminum and water are at 12°C, they will both gain energy and Copper will lose energy

Suppose the final equilibrium temp is 't' then

Energy gained by Aluminum + energy gained by water = energy lost by copper

m₁c₁(t-12) + m₂c₂(t-12) = m₃c₃(245-t)

solve for 't'.

For me to calculate the value, I would need exact units of all the quantities involved. The units stated for heat capacity of Al is really the unit of latent heat. That of water and some of the masses do not have any stated units. While I can assume units, if you want it solved for a numerical value, please send in all related units and I will be happy to solve it for you However, you should be able to solve the equation all on your own.

Mr A