Rajesh P. answered 02/09/20
Experienced Physics Tutor
(0 m) A------------------------------------------------------------------------------------------------------------------------B (222 m)
C---------B
8 m/s x 2 s = 16 m
A students goes 222 m in one direction. Student's speeds is immaterial here.
Then student turns around and jogs for t=2 seconds at a speed of v=8 m/s.
The distance traveled in reverse direction is d = vt = 8 m/s x 2 s = 16 m.
So the net distance of the student from starting position is d = 222 m - 16 m = 206 m