Commenwealth A.
asked • 02/03/20The interactions of Matter
How many moles of 
are required to create 9.54 liters of a 3.4 M solution?
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1 Expert Answer
Frank A. answered • 02/04/20
Tutor
5
(16)
Knowledge, experience and insight from decades of teaching physics.
A 3.4M solution means 3.4 moles/Liter. Irrespective of the substance involved, every liter of that solution will have 3.4 moles of the solute. If you need 9.54 liters instead of just 1, then all you have to do is multiply the moles in each liter by the number of liters. 3.4x9.54=32 moles. (2 sig fig)
Now, if you were looking to find the number of grams of sodium carbonate in 9.54 L of a 3.4M solution, all you need to do is multiply the number of moles in 9.54 liters by the molar mass of sodium carbonate
molar mass of Na2CO3 = (23x2)+12+(16x3) = 106g
Multiply 32.436moles by 106g and you get 3438.216g = 3400g (2 sig fig)
If you need further clarification, please let me now.
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Stanton D.
Hi Commenwealth A., you can set up this problem using "dimensional analysis". Your data have units of "L" and "moles/L," attached, so logically what must you do with them to get something with only the units "moles"? It should be pretty obvious --- ?02/03/20