Find the slope-intercept equation of the line that satisfies the given conditions. passes through (3, −5) and is parallel to 5x + y = 3

Answer 1

Put the equation in the format y = mx + b. m is the slope, and any parallel line will have the same slope, and any perpendicular line will have a slope that is the negative reciprocal. Example: the slope of a line is 2. the perpendicular line will have a slope of -1/2

Once you have the slope, use the give point to find b (simply plug in the values for y, x, and m, and solve for b

Answer 2

y=mx+b m== slope, b==y-intercept

We know a point on the line--i.e. our desired equation is satisfied when (x,y)==(3,-5)

We know our equation looks like the above

So we know y = mx+ b = -5 = 3m+b (plugging in x=3, when y=-5 (equivalent to y=-5 when x=3)

We also know the line is parallel to y=3-5x (rearranging 5x+y=3)

What does this mean? We know the slope (parallel lines have equal slopes)

So we write what we know and see what happens. . .

3m+b= -5

m=-5

Plugging m=-5 into the upper equation yields:

-15+b = -5

OR b=10

we thus have y = -5x + 10

(check by plugging in x=3 and getting back y=-5; and reaffirm the equations have equivalent slopes)