Hi Sarah N.,
It is always good to see a picture or plot a graph. I plotted a graph with the price on the y-axis and items on the x-axis.
For the y-axis I went up a distance and marked $140, and then went up twice that distance plus and marked $260. On the x-axis I went to the right a distance and marked 980 and a slight bit more marked 1014, then I went almost twice that distance and marked 1734 and a bit more and marked 1820.
Next I plotted the demand points (1734, $140) and (1014, $260) and connected them with a line (negative slope). Then I plotted the supply points (980, $140) and (1820, $260) and connected them with a line (positive slope).
You can see the intersection of the two linear lines which is the equilibrium.
You can create a linear equation for both lines and find their intersections. Using m = (y2 - y1)/(x2 - x1) to find the slope. Then use (y - y1) = m(x - x1) to find the linear equations. At the intersection y2 = y1, so you can set the equations equal to each other and solve for x. Then take that x value, plug it back in to one of the equations and solve for y. Your equilibrium will be these (x, y) values.
I am hoping I didn't need to explain the last paragraph to you and you can take it from here.
I hope this helps, Joe.
P.S. The answer I came up with is (1386, $198). So at a price of $198, the supply and demand are equal at 1386. If you need more help, let me know.
Sam Z.
m1x1=m2x2; in your case; quanitty1price1=quanity2price202/01/20