Arthur D. answered 01/26/20
Mathematics Tutor With a Master's Degree In Mathematics
y=x^2-6x+8
complete the square
y=x^2-6x +8
y=x^2-6x+9-9+8
y=(x-3)^2-1
vertex=(3,-1)
set y=0 to find the x-intercepts
0=x^2-6x+8
factor
(x-4)(x-2)=0
x-4=0
x=4 is one x-intercept
x-2=0
x=2 is the other x-intercept
set x=0 to find the y-intercept
y=0^2-6*0+8
y=8 is the y-intercept