A parcel of land is 7 ft longer than it is wide. Each diagonal from one corner to the opposite corner is 203 ft long. What are the dimensions of the parcel?

Question

need the width and the lengh

Answer 1

Pythagorean says:

x^2 + (x+7)^2 = 203^2

x^2 + x^2 + 14x + 49 = 41209

2x^2 + 14x - 41160 = 0

x^2 + 7x - 20580 = 0

(x + 147)(x-140) = 0

x+147 = 0 is disqualified because it results in negative measures

x-140 = 0 ---> x=140

the width is 140, the length is 147

Answer 2

width = w

l= w+7

using Pythagorean theorem= w squared + (w+7)squared =203 squared

W^2 + w^2 +14w +49 =41209

2w^2 +14w =41160

Factor

2w^2 +14w - 41160= 0

factor

2(w^2+7w-20580) =0

2(w_+147)(w-140) = 0 w=-147; which can not be the answer being negative. w =140. .l =147

Answer 3

w² + (w + 7)² = 203² Pythagoras

Can you solve for w and answer?