Find an equation of the circle that satisfies the given conditions. Center (2,-3) and passes through (9,2)

Question

Give the answers in terms of x and y.

Answer 1

(x-h)^2 + (y-k)^2 = r^2 is the general equation for a circle in the x-y plane centered at (h,k) with radius r.

r = sqrt((9-2)^2 + (2-(-3))^2) = 8.

So our circle is (x-2)^2 + (y+3)^2 = 8^2.