
Tabitha D. answered 01/17/20
Experienced Precalculus Tutor Who Can Explain ‘Why’
I’ll help with number 1:
11π/6 = -π/6 so it’s in Quadrant 4
Only cosine is positive in Q4
The reference angle is π/6 or 30°
sin(π/6) = 1/2, so
sin (11π/6) = -1/2
cos(π/6) = √3/2, so
cos(11π/6) = √3/2
tan(π/6) = 1/2 / √3/2 = 1√3 = √3/3, so
tan(11π/6) = -√3/3
csc(11π/6) = the reciprocal of sin(11π/6), so
csc(11π/6) = -2
sec(11π/6) = the reciprocal of cos(11π/6), so
sec(11π/6) = 2√3 /3
cot(11π/6) = the reciprocal of tan(11π/6), so
cot(11π/6) = -√3