
Arturo O. answered 01/10/20
Experienced Physics Teacher for Physics Tutoring
There may be more than one way to work this problem. Here is the approach that comes to mind:
The trajectory from the jumping point to the top of the waterfall must follow a parabola given by
y(x) = (tanθ)x - [g / (2v2cos2θ)]x2
Assuming the salmon starts at point (0,0), it reaches the top of the waterfall at point (1.73, 0.55).
Plug these numbers into the equation for y(x) and solve for v:
x = 1.73 m
y = 0.55 m
θ = 32°
g = 9.8 m/s2
You will get an equation that you can solve for v. Try it.