A 500 kg satellite is accelerated at the rate of 25 m /s while the satellite travels 2.9 km. How much work is done by the satellite’s engine?

Question

The answer is 3.6 x 10^7 J I just don't know how to get there

Answer 1

For this question work done = force applied * distance traveled

Force applied is given by Newton's second law F = ma, F (Newtons) = 500 kg * 25 m/s²,

***** units for acceleration is m/s² not m/s

Now you have force applied and distance traveled (2.9 km = 2900 m) multiply them and you will get work done in Joules (J)